Linear Algebra Examples

$8 x - 3 y + 12 = 0$

Step 1

Move all terms not containing $y$ to the right side of the equation.

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Step 1.1

Subtract $8 x$ from both sides of the equation.

$- 3 y + 12 = - 8 x$

Step 1.2

Subtract $12$ from both sides of the equation.

$- 3 y = - 8 x - 12$

Step 2

Divide each term in $- 3 y = - 8 x - 12$ by $- 3$ and simplify.

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Step 2.1

Divide each term in $- 3 y = - 8 x - 12$ by $- 3$ .

$\frac{- 3 y}{- 3} = \frac{- 8 x}{- 3} + \frac{- 12}{- 3}$

Step 2.2

Simplify the left side.

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Step 2.2.1

Cancel the common factor of $- 3$ .

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Step 2.2.1.1

Cancel the common factor.

$\frac{- 3 y}{- 3} = \frac{- 8 x}{- 3} + \frac{- 12}{- 3}$

Step 2.2.1.2

Divide $y$ by $1$ .

$y = \frac{- 8 x}{- 3} + \frac{- 12}{- 3}$

Step 2.3

Simplify the right side.

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Step 2.3.1

Simplify each term.

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Step 2.3.1.1

Dividing two negative values results in a positive value.

$y = \frac{8 x}{3} + \frac{- 12}{- 3}$

Step 2.3.1.2

Divide $- 12$ by $- 3$ .

$y = \frac{8 x}{3} + 4$

Step 3

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

Interval Notation:

$(- \infty, \infty)$

Set-Builder Notation:

${x | x \in ℝ}$

Step 4